T^3-t^2-25t=-25

Solution for T^3-t^2-25t=-25 equation:

^3-T^2-25T=-25

We move all terms to the left:

^3-T^2-25T-(-25)=0

We add all the numbers together, and all the variables

-1T^2-25T=0

a = -1; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·(-1)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$T_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$T_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$T_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*-1}=\frac{0}{-2}
=0
$
$T_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*-1}=\frac{50}{-2}
=-25
$